当前位置 博文首页 > linux系统中的列出敏感用户的脚本代码

    linux系统中的列出敏感用户的脚本代码

    作者:admin 时间:2021-02-20 15:42

    此处的敏感用户是指这个用户属于多个组,或者这个用户属于的组名跟这个用户名不一样

    #! /bin/bash 
    #list user who belong to more than one group 
    #and list user who belong to the group which isn't the same as the username 
    #w is whitelist,we will not think user in this whitelist is special or dangerous w=("root" "adm" "games" "operator" "halt" "shutdown" "sync" "daemon" "bin" "operator") function WhiteList() 
    { 
        for i in ${w[@]} 
        do
            if [ "$i" == "$1" ];then
                return 1 
            fi
        done
        return 0 
    } 
    IFS=" 
    " for LINE in `cat /etc/passwd|awk -F: '{print $1}'` do
        WhiteList $LINE; 
        #if $? equal 1,means it is in the whitelist     if [ $? -eq 0 ];then
            a=`groups $LINE|awk -F: '{print $2}'` 
            b=`echo $a` 
            if [ "$b" != "$LINE" ];then
                #echo $LINE             echo `groups $LINE` 
            fi
        fi done
    js
下一篇:没有了