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    opencv实现回形遍历像素算法

    作者:ancy_i_cv 时间:2021-07-16 18:50

    本文实例为大家分享了opencv实现回形遍历像素算法的具体代码,供大家参考,具体内容如下

    代码实现

    # -*- coding:utf-8 -*-
    import cv2
    import numpy as np
     
    cv2.namedWindow('img', 0)
     
     
    def traversePixelByCycloidLine(image):
     """
     从一副灰度图像的中心开始向边缘按回形线的方式遍历所有像素,每个像素只能访问一次。
     我目前实现了基本的算法, 但存在以下问题:
     1) 只支持方阵, 且行列为奇数
     2) 只实现, 代码没整理
     """
     
     h, w = image.shape[:2]
     
     assert h == w and h % 2 == 1, '只支持方阵, 且行列为奇数'
     
     center_x, center_y = [w // 2, h // 2]
     
     traverse_num = h * w
     
     cycloid_num = 0
     value = 1
     while True:
     
      for i in range(cycloid_num * 2 + 1):
       if value >= traverse_num:
        return image
       center_x = center_x + 1
       image[center_y, center_x] = 255
       value += 1
       cv2.imshow('img', image)
       cv2.waitKey(33)
     
      for i in range(cycloid_num * 2 + 1):
       if value >= traverse_num:
        return image
       center_y = center_y + 1
       image[center_y, center_x] = 255
       value += 1
       cv2.imshow('img', image)
       cv2.waitKey(33)
     
      for i in range(cycloid_num * 2 + 2):
       if value >= traverse_num:
        return image
       center_x = center_x - 1
       image[center_y, center_x] = 255
       value += 1
       cv2.imshow('img', image)
       cv2.waitKey(33)
     
      for i in range(cycloid_num * 2 + 2):
       if value >= traverse_num:
        return image
       center_y = center_y - 1
       image[center_y, center_x] = 255
       value += 1
       cv2.imshow('img', image)
       cv2.waitKey(33)
      cycloid_num += 1
     
     
    image_wh = 11
     
    while True:
     image = np.zeros((image_wh, image_wh, 3), dtype=np.uint8)
     traversePixelByCycloidLine(image)

    效果展示

    jsjbwy
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