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    golang顺时针打印矩阵的方法示例

    作者:ifcoder 时间:2021-07-07 17:42

    题目描述

    输入一个矩阵,按照从外向里以顺时针的顺序依次打印出每一个数字,例如,如果输入如下4 X 4矩阵: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 则依次打印出数字1,2,3,4,8,12,16,15,14,13,9,5,6,7,11,10.

    package main
    
    import "fmt"
    
    func main() {
      //s := [][]int{{1, 2, 3, 4}, {5, 6, 7, 8}, {9, 10, 11, 12}, {13, 14, 15, 16}}
      //s := [][]int{{1}, {2}, {3}, {4}}
      //s := [][]int{{1, 2, 3, 4}, {5, 6, 7, 8}}
      s := [][]int{{1, 2}, {5, 6}, {9, 10}, {13, 14}}
    
      printMatrix(s)
    }
    func printMatrix(s [][]int) {
      if s == nil {
        fmt.Println("切片为空,无法打印")
      }
      bex, bey := 0, 0
      hang := len(s) - 1
      lie := len(s[0]) - 1
      if hang == 0 {
        for _, v := range s[0] {
          fmt.Println(v)
        }
        return
      }
      if lie == 0 {
        for _, v := range s {
          fmt.Println(v[0])
        }
        return
      }
      for bex <= hang && bey <= lie {
        ax, ay := bex, bey
        for ay < lie {
          fmt.Println(s[ax][ay])
          ay++
        }
        for ax < hang {
          fmt.Println(s[ax][ay])
          ax++
        }
        for ay > bey {
          fmt.Println(s[ax][ay])
          ay--
        }
        for ax > bex {
          fmt.Println(s[ax][ay])
          ax--
        }
        bex++
        bey++
        hang--
        lie--
      }
    }
    
    
    jsjbwy
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