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    自动重启服务的shell脚本代码

    作者:admin 时间:2021-02-12 18:08

    复制代码 代码如下:

    #!/bin/bash
    if [ ! -f /tmp/down_count ];then
    echo "0" > /tmp/down_count
    fi
    curl -I tomcat-host -o "/tmp/status" >/dev/null 2>&1
    code=`awk 'NR==1 {print $2}' /tmp/status`
    if [ "$[code]" -ge 500 ];then
    down=`expr $(cat /tmp/down_count) + 1`
    echo "$down" > /tmp/down_count
    if [ "$down" -gt 3 ];then
    if [ ! -f "/tmp/restart_count" ];then
    echo "0" > /tmp/restart_count
    fi
    restart_count=`expr $(cat /tmp/restart_count) + 1`
    echo "$restart_count" > /tmp/restart_count
    if [ "$restart_count" -le 2 ];then
    echo "tomcat down at `date`" >> /tmp/down_info
    /etc/init.d/tomcat6 restart
    fi
    fi
    else
    echo "0" > /tmp/down_count
    echo "0" > /tmp/restart_count
    fi


    脚本实现了,当检测网页状态码大于等于500连续出现3次数,自动重启tomcat6,且只连续重启两次。 js