当前位置 博文首页 > python实现K折交叉验证

    python实现K折交叉验证

    作者:Jepson2017 时间:2021-07-03 18:32

    本文实例为大家分享了python实现K折交叉验证的具体代码,供大家参考,具体内容如下

    用KNN算法训练iris数据,并使用K折交叉验证方法找出最优的K值

    import numpy as np
    from sklearn import datasets
    from sklearn.neighbors import KNeighborsClassifier
    from sklearn.model_selection import KFold # 主要用于K折交叉验证
    
    # 导入iris数据集
    iris = datasets.load_iris()
    X = iris.data
    y = iris.target
    print(X.shape,y.shape)
    
    # 定义想要搜索的K值,这里定义8个不同的值
    ks = [1,3,5,7,9,11,13,15]
    
    # 进行5折交叉验证,KFold返回的是每一折中训练数据和验证数据的index
    # 假设数据样本为:[1,3,5,6,11,12,43,12,44,2],总共10个样本
    # 则返回的kf的格式为(前面的是训练数据,后面的验证集):
    # [0,1,3,5,6,7,8,9],[2,4]
    # [0,1,2,4,6,7,8,9],[3,5]
    # [1,2,3,4,5,6,7,8],[0,9]
    # [0,1,2,3,4,5,7,9],[6,8]
    # [0,2,3,4,5,6,8,9],[1,7]
    kf = KFold(n_splits = 5, random_state=2001, shuffle=True)
    
    # 保存当前最好的k值和对应的准确率
    best_k = ks[0]
    best_score = 0
    
    # 循环每一个k值
    for k in ks:
        curr_score = 0
        for train_index,valid_index in kf.split(X):
            # 每一折的训练以及计算准确率
            clf = KNeighborsClassifier(n_neighbors=k)
            clf.fit(X[train_index],y[train_index])
            curr_score = curr_score + clf.score(X[valid_index],y[valid_index])
            
        # 求一下5折的平均准确率
        avg_score = curr_score/5
        if avg_score > best_score:
            best_k = k
            best_score = avg_score
        print("current best score is :%.2f" % best_score,"best k:%d" %best_k)
        
    print("after cross validation, the final best k is :%d" %best_k)

    jsjbwy