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    获取两个日期间隔时间的shell脚本代码

    作者:admin 时间:2021-02-12 15:05

    复制代码 代码如下:

    #!/bin/sh
    # 获取所在季度的第一天,到昨天的日期间隔
    # link:www.jb51.net
    # date:2013/2/28

    day=`date -d "1 days ago " "+%Y%m%d"`;
    year=`expr substr ${day} 1 4`;
    month=`expr substr ${day} 5 2`;
    s_date=$year"0101"
    if [ "$month" == "01" ] || [ "$month" == "02" ] || [ "$month" == "03" ];then
       s_date=$year"0101"
    elif [ "$month" == "04" ] || [ "$month" == "05" ] || [ "$month" == "06" ];then
       s_date=$year"0401"
    elif [ "$month" == "07" ] || [ "$month" == "08" ] || [ "$month" == "09" ];then
       s_date=$year"0701"
    elif [ "$month" == "10" ] || [ "$month" == "11" ] || [ "$month" == "12" ];then
       s_date=$year"1001"
    fi
    e_date=$day
    sys_s_data=`date -d "$s_date" +%s`
    sys_e_data=`date -d "$e_date" +%s`
    interval=`expr $sys_e_data - $sys_s_data`
    daycount=`expr $interval / 3600 / 24 + 1`

    echo $daycount

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